Miller compensates for the interferometer drift or slope over each page, ie 20 turns. Advantage calculation are on single page.

I could do the same over whole day: 24h * 60t/h = 1440 turns. The daily compensation could change could be overall zero but be cyclic over day. This would cause a daily cycle in the interferometric sin component, albeit 1/1440 as large each day.

Or even an entire set of days in name-list.

Effect of slope on sin[ ] in interval 2 Pi.

Fourier analysis assumes that a signal repeats every cycle. If a signal does not do this, then FA cannot be used. At least without closing the cycle or the like. This program shows that when the “c” parameter is removed from the model expression, then the “a” parameter increases wildly. But when the “c” is present, the “a” parameter matches the “a1” in the data(xy) generation code.

FindFit test

also to find out how to structure “data”=x_0.5_1._1.5_2._2.5_3._3.5_4._4.5_5._5.5_6._6.5_7._7.5_8._8.5_9._9.5_10._xy_0.5_30.3197_1._35.6081_1.5_40.837_2._45.9839_2.5_51.0346_3._55.9839_3.5_60.837_4._65.6081_4.5_70.3197_5._75._5.5_79.6803_6._84.3919_6.5_89.163_7._94.0161_7.5_98.9654_8._104.016_8.5_109.163_9._114.392_9.5_119.68_10._125

angles {0.314159,0.628319,0.942478,1.25664,1.5708,1.88496,2.19911,2.51327,2.82743,3.14159,3.45575,3.76991,4.08407,4.39823,4.71239,5.02655,5.34071,5.65487,5.96903,6.28319}

ff {a→1.03457,b→25.,c→10.} </code>